-4=t^2-4t

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Solution for -4=t^2-4t equation: 



-4=t^2-4t

We move all terms to the left:

-4-(t^2-4t)=0

We get rid of parentheses

-t^2+4t-4=0

We add all the numbers together, and all the variables

-1t^2+4t-4=0

a = -1; b = 4; c = -4;
Δ = b2-4ac
Δ = 42-4·(-1)·(-4)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{-4}{-2}=+2$

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